IGCSE Physics Notes

Examination Year: 2025–2027
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igcse Motion, forces and energy

Cambridge IGCSE Physics
Syllabus: 2025–2027

Measuring Length & Time

Measuring Length

SI unit: metre (m).

  • Measuring tape — for curved lengths. Smallest reading: about 1 mm.
  • Metre rule — for linear lengths. Smallest reading: typically 0.1–1.0 cm (depends on graduations).
  • Micrometer screw gauge — for very small thickness. Least count: 0.01 mm.
Using a Rule (avoid parallax error)
  1. Place the scale right next to the object; align one end with zero (or note exact start mark).
  2. Place eye perpendicular to the mark at the other end.
  3. If you didn’t start at zero, compute final − initial.
Examples
  • Offset start: Start 1.0 cm, end 3.7 cm → length = 2.7 cm.
  • Rolling cylinder (2 turns): Start 2 cm, end 28 cm → total = 26 cm for 2 turns → circumference = 13 cm.

Micrometer Screw Gauge

  • Place the object between the anvil and spindle.
  • Tighten with the ratchet for consistent contact.
  1. Main (sleeve) scale: read mm (and half-mm), e.g. 2.5 mm.
  2. Thimble scale: divisions × 0.01 mm, e.g. 46 → 0.46 mm.
  3. Total = 2.5 + 0.46 = 2.96 mm.
Precaution

For sheets/wires, take several readings at different points and use the average.

Measuring Time

Instrument: Stopwatch. SI unit: second (s).

Pendulum Method (time period)
  1. Displace the bob by a small angle (≈ ≤15°).
  2. Start timing as it passes the reference point; count 20 oscillations.
  3. Stop timing; compute average period T = \u0074\u006F\u0074\u0061\u006C \u0074\u0069\u006D\u0065 / 20.
Useful Relations

T = 2π √(L / g) (simple pendulum)     a = Δv / Δt

Accuracy & Good Practice
  • Begin/end timing exactly at the reference point.
  • Repeat trials and take the average.
  • Quote values with appropriate significant figures; include units.
  • Check for zero error and avoid parallax.

Scalars and Vectors

A scalar quantity has magnitude only. Examples: distance, speed, time, mass, energy, temperature.

A vector quantity has both magnitude and direction. Examples: force, weight, velocity, acceleration, momentum, electric field strength, gravitational field strength.

Key Formula

For perpendicular vectors: Resultant (R) = √(X² + Y²)

Example — Addition of Forces

Step-by-step
  • 15 N East and 10 N North → perpendicular vectors.
  • R = √(15² + 10²) = √325 ≈ 18 N, direction: North-East.

Graphical Representation

Use the head-to-tail method and scale diagrams.

Common Mistake

Forgetting to include direction when writing a vector result.

Motion

Speed & Velocity

Speed (scalar): v = d/t. Velocity (vector): v = Δs/Δt.

Distance–Time Graphs

  • Slope = speed; straight line = constant speed; horizontal = rest.
  • Curved line ⇒ changing speed; tangent’s slope = instantaneous speed.

Speed/Velocity–Time Graphs

  • Slope = acceleration; area under graph = distance (or displacement).
  • Horizontal = constant velocity; straight incline = uniform acceleration.
Constant Acceleration (SUVAT)
  • v = u + at
  • s = ut + ½at²
  • v² = u² + 2as
Example

Car from rest to 20 m/s in 10 s: a = (20−0)/10 = 2 m/s²; distance = area = ½×10×20 = 100 m.

Free Fall & Terminal Velocity

  • In free fall (no air resistance), a = g ≈ 9.8 m/s² downward.
  • With air resistance, acceleration falls; at terminal velocity forces balance.

Free Fall & Motion Graphs

Kinematics (Constant a)

Equations
  • v = u + a t
  • s = u t + ½ a t²
  • v² = u² + 2 a s
Worked Example

Throw up: u=14, a=−9.8. Top time t=14/9.8≈1.43 s; height ≈10 m.

Graph Reminders

  • s–t slope ⇒ velocity; v–t slope ⇒ acceleration; v–t area ⇒ displacement.
  • Negative v region ⇒ opposite direction.
Common Mistakes
  • Using wrong sign for g.
  • Mixing speed vs velocity on signed graphs.

Centre of Gravity

Definition

The centre of gravity (CG) is the point at which the resultant weight of a body (or system of particles) acts — i.e. the theoretical point where all the body’s weight can be considered to be concentrated.

Note: The CG does not have to lie inside the material of the body. Examples: a tyre (ring), a football helmet; even human body positions (e.g. a high-jumper in flight) can have CG outside the body.

Finding the CG of an Irregular Lamina (Plumb-line Method)

  1. Punch three small holes near different edges of the lamina.
  2. Suspend the lamina from the first hole on a stand. Hang a plumb-line close to that hole (without touching the lamina).
  3. Let the system come to rest; draw a line on the lamina along the plumb-line.
  4. Repeat the suspension from the second and third holes; draw the second and third vertical lines.
  5. The point where the lines intersect is the centre of gravity (G).

Keep the plumb-line clear of the lamina and wait until it is completely at rest before marking each line.

Stability & the Position of CG

  • An object will topple when the vertical line through its CG falls outside its base of support.
  • A lower CG → greater stability (harder to topple).
  • Example: The Leaning Tower of Pisa doesn’t topple because its CG remains vertically above the base.

Quick Checks

  • Q: Why do racing cars have very low chassis?
    A: Lower CG increases stability when cornering.
  • Q: A cabinet is more stable with a wider base. Why?
    A: The base of support is larger, so the CG line stays within the base for larger tilts.

igcse Momentum

Definition of Momentum

Every moving object has linear momentum. It is defined as the product of mass and velocity.

Key Formula

p = m v \; \text{ (units: kg·m/s) }

Vector! Always include a sign/direction for momentum.

Newton’s Second Law (Momentum Form)

The rate of change of momentum of a body is proportional to the net force and occurs in the same direction.

Key Formula

F_\text{net} = \dfrac{\Delta p}{\Delta t}

If mass is constant, this reduces to F = m a.

Impulse

Impulse is the change in momentum produced by a force acting for a time.

[formula]J = F\,\Delta t = \Delta p \quad \text{(units: N·s = kg·m/s)}[/formula>
Idea

A bouncing ball undergoes a larger change in momentum than one that is simply caught, so the impulse (and peak force) is larger.

Principle of Conservation of Momentum

In an isolated system, the total momentum remains constant during any interaction (e.g., collision).

  1. Choose a positive direction (e.g., right).
  2. Write total p before = total p after.
  3. Substitute signs for directions and solve.

Do not add speeds; use signed velocities.

Worked Examples

1) Gun Recoil

A bullet of mass 0.03 kg leaves a gun at 1000 m/s. The gun’s mass is 1.5 kg. Find the recoil speed of the gun (take forward as +).

  1. Total momentum before firing = 0.
  2. After: p_\text{bullet} + p_\text{gun} = 0(0.03)(+1000) + (1.5)v_g = 0.
  3. v_g = - (0.03×1000)/1.5 = -20 m/s (20 m/s backward).
2) Two Carts (Inelastic)

Cart A (0.80 kg) at +3.0 m/s sticks to Cart B (0.40 kg) at −1.0 m/s. Find their common speed immediately after collision.

  1. p_\text{before} = 0.80×(+3.0) + 0.40×(−1.0) = 2.4 − 0.4 = 2.0 kg·m/s.
  2. Total mass = 1.20 kg ⇒ v = 2.0/1.20 ≈ 1.67 m/s (forward).

Quick Practice

  • A 0.20 kg ball changes velocity from +8.0 m/s to −6.0 m/s in 0.040 s. Find the average force.
  • Two skaters (45 kg and 60 kg) push off each other and move apart with 1.8 m/s for the lighter one. Find the other’s speed and direction.
  • A 2.0 kg trolley receives a 5.0 N force for 0.30 s. Find its impulse and change in speed.
Summary
  • p = m v (vector); J = \Delta p = F \Delta t
  • F_\text{net} = \dfrac{\Delta p}{\Delta t} (→ F=ma if m const.)
  • Isolated system ⇒ total momentum conserved in all interactions.

igcse Energy, Work & Power

Key Ideas

  • Energy is the ability to do work. Unit: joule (J).
  • Work is energy transferred when a force moves an object. Unit: joule (J).
  • Power is the rate of doing work or transferring energy. Unit: watt (W).
Core Formulas

Work (W) = Force (F) × distance (d)   (force in the direction of motion)

Power (P) = Work (W) ÷ time (t) = Energy transferred (E) ÷ time (t)

Kinetic energy (E_k) = 1/2 × m × v^2

Change in gravitational potential energy (ΔE_p) = m × g × Δh

Directions Matter

If the force is not along the direction of motion, use W = F × d × cos(theta).

Units & Symbols

QuantitySymbolUnitNotes
WorkWJ1 J = 1 N·m
EnergyEJSame unit as work
PowerPW1 W = 1 J/s
Massmkg
Speedvm/s
GravitygN/kg≈ 9.8 N/kg
Height changeΔhm
Timets
ForceFN
Distance (along force)dm

Efficiency

How well a device converts input energy (or power) into useful output.

Efficiency (%) = (useful energy out ÷ total energy in) × 100%

Efficiency (%) = (useful power out ÷ total power in) × 100%

Common Mistakes
  • Mixing energy and power in the same calculation.
  • Forgetting to convert minutes or hours to seconds when using power.
  • Using total distance instead of distance moved in the force direction.

Worked Examples

1) Work Done by a Force

A box is pushed with a constant force of 50 N over 6.0 m along a level floor.

Work: W = F × d = 50 × 6.0 = 300 J.

2) Power from Energy per Time

An electric motor lifts 800 J of energy every 4 s.

Power: P = E ÷ t = 800 ÷ 4 = 200 W.

3) Gravitational Potential Energy

A 2.5 kg book is raised by 1.2 m.

ΔE_p: = m × g × Δh = 2.5 × 9.8 × 1.2 ≈ 29 J.

4) Kinetic Energy

A 1,000 kg car travels at 12 m/s.

E_k: = 1/2 × 1000 × 12^2 = 72,000 J.

5) Efficiency

A device takes 2,000 J of electrical energy and delivers 1,400 J of useful output.

Efficiency: = (1400 ÷ 2000) × 100% = 70%.

Energy Transfers & Sankey Idea

In any process, total energy is conserved. Useful energy appears in the intended form; the rest is usually lost as heat or sound.

Sankey diagrams help show how input energy splits into useful and wasted outputs. Arrow width represents the amount of energy.

Quick Practice

  • A 600 N student climbs 5.0 m of stairs in 8.0 s. Find the work done and average power.
  • A 60 W lamp is on for 3 hours. How much energy does it use in joules?
  • A 0.40 kg ball speeds up from 5 m/s to 9 m/s. Find the increase in kinetic energy.

Summary: Work links force and distance, energy measures capacity to do work, and power measures how fast it happens. Use consistent units and always check the direction of the force.

Density, Mass & Volume

Definition of Density

Density is the mass per unit volume of a substance. ρ = m / V Units: g/cm³ or kg/m³; 1 g/cm³ = 1000 kg/m³.

Subtopics
  • Density of a liquid
  • Density of a regular solid
  • Density of an irregular solid (displacement)
  • Floating or sinking

Mass & Weight

Mass: quantity of matter (scalar), measured by balance (kg). Weight: gravitational force W = mg (vector), measured by Newton meter (N).

Gravitational field strength g = W/m (N/kg).

Density of a Liquid

  1. Mass of empty cylinder m₁.
  2. Add volume V of liquid; mass m₂.
  3. Mass of liquid = m₂ − m₁.
  4. ρ = (m₂ − m₁)/V.

Keep eye level to avoid parallax.

Density of a Regular Solid

  • Measure dimensions → compute volume.
  • Weigh mass m; ρ = m/V.
ShapeVolume
Cube
Cuboidl×b×h
Cylinderπr²h
Sphere4/3 πr³
Cone1/3 πr²h

Density of an Irregular Solid (Displacement)

  1. Weigh object (mass m).
  2. Use a displacement can → collect displaced water in measuring cylinder.
  3. Volume of object = volume of displaced water.
  4. ρ = m/V.

Avoid trapped air bubbles → they inflate the measured volume.

Float or Sink?

  • Object density < fluid → floats (top layer if immiscible).
  • Object density > fluid → sinks.

Summary Table

QuantityDefinitionFormulaUnitType
MassAmount of matterkgScalar
WeightGravitational forceW = mgNVector
gForce per unit massg = W/mN/kgVector
DensityMass per volumeρ = m/Vkg/m³Scalar

Always convert units correctly (g↔kg, cm³↔m³).

Pressure

Definition & Formula

Pressure is the force acting per unit area.

P = F / A   (Units: N/m² or Pa)

Pressure by Solids

  • For the same force, a smaller area gives a larger pressure (e.g., sharp nails, knives).
  • For the same area, a larger force gives a larger pressure.

Heavy equipment (e.g., cement mixers) are put on wide boards to spread the weight and reduce pressure on soft ground.

Quick Example (solid)

A 4400 N load sits on an 0.50 m² plate. P = 4400 / 0.50 = 8800 Pa (8.8 kPa).

Fluid Pressure

In liquids, pressure increases with depth and depends on density.

P = ρ g h   where ρ is density (kg/m³), g is 9.8–10 N/kg, h is depth (m)

  • At the same depth in a liquid, pressure is the same in all directions.
  • Higher density ⇒ higher pressure at the same depth.

Quick Example (liquid column)

Water of depth 20 m: P = 1000 × 10 × 20 = 2.0 × 10⁵ Pa (200 kPa). On a 0.50 m² gate, F = P × A = 1.0 × 10⁵ N.

Applications

  • Hydraulic brakes: small force at the master cylinder creates a pressure transmitted to larger-area pistons at the wheels, giving a larger force.
  • Sharp tools (nails, needles, knives): small contact area gives high pressure to pierce or cut easily.
  • Reducing pressure: wide skis/tractor tyres/spreading boards increase area to avoid sinking.

Disadvantages / Safety

People confined to bed can develop bed sores where the body’s weight presses on small skin areas; relieve by turning regularly and using soft, wide supports.

Units & Conversions

  • 1 Pa = 1 N/m²
  • 1 kPa = 1000 Pa,   800 kPa = 800 000 Pa
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